Decodes a sequence of characters from their UTF-8 representation. Returns none if the bytes are
not a sequence of Unicode scalar values.
Equations
- b.utf8Decode? = ByteArray.utf8Decode?.go b (b.size + 1) 0 #[] ⋯ ⋯
Instances For
Equations
- b.validateUTF8 = ByteArray.validateUTF8.go b (b.size + 1) 0 ⋯ ⋯
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Equations
Decodes an array of bytes that encode a string as UTF-8 into the corresponding string.
Equations
- String.fromUTF8 a h = { bytes := a, isValidUTF8 := h }
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Decodes an array of bytes that encode a string as UTF-8 into
the corresponding string, or returns none if the array is not a valid UTF-8 encoding of a string.
Equations
- String.fromUTF8? a = if h : a.IsValidUTF8 then some (String.fromUTF8 a h) else none
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Decodes an array of bytes that encode a string as UTF-8 into the corresponding string, or panics if the array is not a valid UTF-8 encoding of a string.
Equations
- String.fromUTF8! a = if h : a.IsValidUTF8 then String.fromUTF8 a h else panicWithPosWithDecl "Init.Data.String.Basic" "String.fromUTF8!" 243 46 "invalid UTF-8 string"
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Appends two strings. Usually accessed via the ++ operator.
The internal implementation will perform destructive updates if the string is not shared.
Examples:
"abc".append "def" = "abcdef""abc" ++ "def" = "abcdef""" ++ "" = ""
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Equations
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Equations
- String.instHSubRaw = { hSub := fun (p : String.Pos.Raw) (s : String) => { byteIdx := p.byteIdx - s.utf8ByteSize } }
Equations
- String.instHAddRaw = { hAdd := fun (s : String) (p : String.Pos.Raw) => { byteIdx := s.utf8ByteSize + p.byteIdx } }
Equations
- String.instHAddRaw_1 = { hAdd := fun (p : String.Pos.Raw) (s : String) => { byteIdx := p.byteIdx + s.utf8ByteSize } }
Equations
- String.instLERaw = { le := fun (p₁ p₂ : String.Pos.Raw) => p₁.byteIdx ≤ p₂.byteIdx }
Equations
- String.instLTRaw = { lt := fun (p₁ p₂ : String.Pos.Raw) => p₁.byteIdx < p₂.byteIdx }
Equations
- String.instDecidableLeRaw p₁ p₂ = inferInstanceAs (Decidable (p₁.byteIdx ≤ p₂.byteIdx))
Equations
- String.instDecidableLtRaw p₁ p₂ = inferInstanceAs (Decidable (p₁.byteIdx < p₂.byteIdx))
Equations
- s₁.decidableLT s₂ = s₁.data.decidableLT s₂.data
Converts a string to a list of characters.
Since strings are represented as dynamic arrays of bytes containing the string encoded using UTF-8, this operation takes time and space linear in the length of the string.
Examples:
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Predicate for validity of positions inside a String.
There are multiple equivalent definitions for validity.
We say that a position is valid if the string obtained by taking all of the bytes up to, but
excluding, the given position, is valid UTF-8; see Pos.isValid_iff_isValidUTF8_extract_zero.
Similarly, a position is valid if the string obtained by taking all of the bytes starting at the
given position is valid UTF-8; see Pos.isValid_iff_isValidUTF8_extract_utf8ByteSize.
An equivalent condition is that the position is the length of the UTF-8 encoding of
some prefix of the characters of the string; see Pos.isValid_iff_exists_append and
Pos.isValid_iff_exists_take_data.
Another equivalent condition that can be checked efficiently is that the position is either the
end position or strictly smaller than the end position and the byte at the position satisfies
UInt8.IsUTF8FirstByte; see Pos.isValid_iff_isUTF8FirstByte.
Examples:
String.Pos.IsValid "abc" ⟨0⟩String.Pos.IsValid "abc" ⟨1⟩String.Pos.IsValid "abc" ⟨3⟩¬ String.Pos.IsValid "abc" ⟨4⟩String.Pos.IsValid "𝒫(A)" ⟨0⟩¬ String.Pos.IsValid "𝒫(A)" ⟨1⟩¬ String.Pos.IsValid "𝒫(A)" ⟨2⟩¬ String.Pos.IsValid "𝒫(A)" ⟨3⟩String.Pos.IsValid "𝒫(A)" ⟨4⟩
- isValidUTF8_extract_zero : (s.bytes.extract 0 off.byteIdx).IsValidUTF8
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Returns the size of the byte slice delineated by the positions lo and hi.
Equations
- lo.byteDistance hi = hi.byteIdx - lo.byteIdx
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Accesses the indicated byte in the UTF-8 encoding of a string.
At runtime, this function is implemented by efficient, constant-time code.
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Equations
- s.getUtf8Byte p h = s.getUTF8Byte p h
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Returns true if p is a valid UTF-8 position in the string s.
This means that p ≤ s.endPos and p lies on a UTF-8 character boundary. At runtime, this
operation takes constant time.
Examples:
String.Pos.isValid "abc" ⟨0⟩ = trueString.Pos.isValid "abc" ⟨1⟩ = trueString.Pos.isValid "abc" ⟨3⟩ = trueString.Pos.isValid "abc" ⟨4⟩ = falseString.Pos.isValid "𝒫(A)" ⟨0⟩ = trueString.Pos.isValid "𝒫(A)" ⟨1⟩ = falseString.Pos.isValid "𝒫(A)" ⟨2⟩ = falseString.Pos.isValid "𝒫(A)" ⟨3⟩ = falseString.Pos.isValid "𝒫(A)" ⟨4⟩ = true
Equations
- String.Pos.Raw.isValid s p = if h : p < s.endPos then decide (s.getUTF8Byte p h).IsUTF8FirstByte else decide (p = s.endPos)
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Equations
Equations
- String.instInhabitedValidPos = { default := s.startValidPos }
Equations
- String.instDecidableLeValidPos l r = decidable_of_iff' (l.offset ≤ r.offset) ⋯
Equations
- String.instDecidableLtValidPos l r = decidable_of_iff' (l.offset < r.offset) ⋯
A region or slice of some underlying string.
A slice consists of a string together with the start and end byte positions of a region of interest. Actually extracting a substring requires copying and memory allocation, while many slices of the same underlying string may exist with very little overhead. While this could be achieved by tracking the bounds by hand, the slice API is much more convenient.
String.Slice bundles proofs to ensure that the start and end positions always delineate a valid
string. For this reason, it should be preferred over Substring.
- str : String
The underlying strings.
The byte position of the start of the string slice.
The byte position of the end of the string slice.
The slice is not degenerate (but it may be empty).
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Equations
- One or more equations did not get rendered due to their size.
Returns a slice that contains the entire string.
Equations
- s.toSlice = { str := s, startInclusive := s.startValidPos, endExclusive := s.endValidPos, startInclusive_le_endExclusive := ⋯ }
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The number of bytes of the UTF-8 encoding of the string slice.
Equations
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Equations
- String.instHAddRawSlice = { hAdd := fun (p : String.Pos.Raw) (s : String.Slice) => { byteIdx := p.byteIdx + s.utf8ByteSize } }
Equations
- String.instHAddSliceRaw = { hAdd := fun (s : String.Slice) (p : String.Pos.Raw) => { byteIdx := s.utf8ByteSize + p.byteIdx } }
Equations
- String.instHSubRawSlice = { hSub := fun (p : String.Pos.Raw) (s : String.Slice) => { byteIdx := p.byteIdx - s.utf8ByteSize } }
The end position of a slice, as a Pos.Raw.
Equations
- s.rawEndPos = { byteIdx := s.utf8ByteSize }
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Offsets p by offset on the left. This is not an HAdd instance because it should be a
relatively rare operation, so we use a name to make accidental use less likely. To offset a position
by the size of a character character c or string s, you can use c + p resp. s + p.
This should be seen as an operation that converts relative positions into absolute positions.
See also Pos.Raw.increaseBy, which is an "advancing" operation.
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Decreases p by offset. This is not an HSub instance because it should be a relatively
rare operation, so we use a name to make accidental use less likely. To unoffset a position
by the size of a character c or string s, you can use p - c resp. p - s.
This should be seen as an operation that converts absolute positions into relative positions.
See also Pos.Raw.decreaseBy, which is an "unadvancing" operation.
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Accesses the indicated byte in the UTF-8 encoding of a string slice.
At runtime, this function is implemented by efficient, constant-time code.
Equations
- s.getUTF8Byte p h = s.str.getUTF8Byte (p.offsetBy s.startInclusive.offset) ⋯
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Accesses the indicated byte in the UTF-8 encoding of the string slice, or panics if the position is out-of-bounds.
Equations
- One or more equations did not get rendered due to their size.
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Creates a String from a String.Slice by copying the bytes.
Equations
- s.copy = s.startInclusive.extract s.endExclusive
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Equations
- String.instInhabitedPos = { default := s.startPos }
Equations
- String.instDecidableLePos l r = decidable_of_iff' (l.offset ≤ r.offset) ⋯
Equations
- String.instDecidableLtPos l r = decidable_of_iff' (l.offset < r.offset) ⋯
Efficiently checks whether a position is at a UTF-8 character boundary of the slice s.
Equations
- String.Pos.Raw.isValidForSlice s p = if h : p < s.rawEndPos then decide (s.getUTF8Byte p h).IsUTF8FirstByte else decide (p = s.rawEndPos)
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Equations
Given a slice and a valid position within the slice, obtain a new slice on the same underlying string by replacing the start of the slice with the given position.
Equations
- s.replaceStart pos = { str := s.str, startInclusive := pos.str, endExclusive := s.endExclusive, startInclusive_le_endExclusive := ⋯ }
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Given a slice and a valid position within the slice, obtain a new slice on the same underlying string by replacing the end of the slice with the given position.
Equations
- s.replaceEnd pos = { str := s.str, startInclusive := s.startInclusive, endExclusive := pos.str, startInclusive_le_endExclusive := ⋯ }
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Given a slice and two valid positions within the slice, obtain a new slice on the same underlying string formed by the new bounds, or panic if the given end is strictly less than the given start.
Equations
- One or more equations did not get rendered due to their size.
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Equations
- s.decodeChar byteIdx h = s.bytes.utf8DecodeChar byteIdx h
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Returns the byte at the given position in the string, or panicks if the position is the end position.
Equations
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Returns the character at the position pos of a string, taking a proof that p is not the
past-the-end position.
This function is overridden with an efficient implementation in runtime code.
Examples:
("abc".pos ⟨1⟩ (by decide)).get (by decide) = 'b'("L∃∀N".pos ⟨1⟩ (by decide)).get (by decide) = '∃'
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Returns the character at the position pos of a string, or none if the position is the
past-the-end position.
This function is overridden with an efficient implementation in runtime code.
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Returns the character at the position pos of a string, or panics if the position is the
past-the-end position.
This function is overridden with an efficient implementation in runtime code.
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Given a position in s.replaceStart p₀, obtain the corresponding position in s.
Equations
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Given a position in s that is at least p₀, obtain the corresponding position in
s.replaceStart p₀.
Equations
- p₀.toReplaceStart pos h = { offset := pos.offset.unoffsetBy p₀.offset, isValidForSlice := ⋯ }
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Given a position in s.replaceEnd p₀, obtain the corresponding position in s.
Equations
- String.Slice.Pos.ofReplaceEnd pos = { offset := pos.offset, isValidForSlice := ⋯ }
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Given a position in s that is at most p₀, obtain the corresponding position in s.replaceEnd p₀.
Equations
- p₀.toReplaceEnd pos h = { offset := pos.offset, isValidForSlice := ⋯ }
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Advances p by n bytes. This is not an HAdd instance because it should be a relatively
rare operation, so we use a name to make accidental use less likely. To add the size of a
character c or string s to a raw position p, you can use p + c resp. p + s.
This should be seen as an "advance" or "skip".
See also Pos.Raw.offsetBy, which turns relative positions into absolute positions.
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Move the position p back by n bytes. This is not an HSub instance because it should be a
relatively rare operation, so we use a name to make accidental use less likely. To remove the size
of a character c or string s from a raw position p, you can use p - c resp. p - s.
This should be seen as the inverse of an "advance" or "skip".
See also Pos.Raw.unoffsetBy, which turns absolute positions into relative positions.
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Advances a valid position on a slice to the next valid position, given a proof that the position is not the past-the-end position, which guarantees that such a position exists.
Equations
- pos.next h = { offset := pos.offset.increaseBy ((pos.byte h).utf8ByteSize ⋯), isValidForSlice := ⋯ }
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Advances a valid position on a slice to the next valid position, or panics if the given position is the past-the-end position.
Equations
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Equations
- One or more equations did not get rendered due to their size.
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Returns the previous valid position before the given position, given a proof that the position is not the start position, which guarantees that such a position exists.
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Returns the previous valid position before the given position, or panics if the position is the start position.
Equations
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Advances a valid position on a string to the next valid position, given a proof that the position is not the past-the-end position, which guarantees that such a position exists.
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Advances a valid position on a string to the next valid position, or returns none if the
given position is the past-the-end position.
Equations
- pos.next? = Option.map String.Slice.Pos.ofSlice pos.toSlice.next?
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Returns the previous valid position before the given position, given a proof that the position is not the start position, which guarantees that such a position exists.
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Returns the previous valid position before the given position, or none if the position is
the start position.
Equations
- pos.prev? = Option.map String.Slice.Pos.ofSlice pos.toSlice.prev?
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Constructs a valid position on s from a position, returning none if the position is not valid.
Equations
- s.pos? off = Option.map String.Slice.Pos.ofSlice (s.toSlice.pos? off)
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Given a byte position within a string slice, obtains the smallest valid position that is strictly greater than the given byte position.
Equations
- String.Slice.findNextPos offset s _h = String.Slice.findNextPos.go✝ s offset.inc
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Equations
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Returns the character at position p of a string. If p is not a valid position, returns the
fallback value (default : Char), which is 'A', but does not panic.
This function is overridden with an efficient implementation in runtime code. See
String.Pos.Raw.utf8GetAux for the reference implementation.
This is a legacy function. The recommended alternative is String.ValidPos.get, combined with
String.pos or another means of obtaining a String.ValidPos.
Examples:
"abc".get ⟨1⟩ = 'b'"abc".get ⟨3⟩ = (default : Char)because byte3is at the end of the string."L∃∀N".get ⟨2⟩ = (default : Char)because byte2is in the middle of'∃'.
Equations
- String.Pos.Raw.get s p = String.Pos.Raw.utf8GetAux s.data 0 p
Instances For
Equations
- s.get p = String.Pos.Raw.utf8GetAux s.data 0 p
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Returns the character at position p of a string. If p is not a valid position, returns none.
This function is overridden with an efficient implementation in runtime code. See
String.utf8GetAux? for the reference implementation.
This is a legacy function. The recommended alternative is String.ValidPos.get, combined with
String.pos? or another means of obtaining a String.ValidPos.
Examples:
Equations
- String.Pos.Raw.get? x✝¹ x✝ = String.Pos.Raw.utf8GetAux? x✝¹.data 0 x✝
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Equations
- x✝¹.get? x✝ = String.Pos.Raw.utf8GetAux? x✝¹.data 0 x✝
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Returns the character at position p of a string. Panics if p is not a valid position.
See String.pos? and String.ValidPos.get for a safer alternative.
This function is overridden with an efficient implementation in runtime code. See
String.utf8GetAux for the reference implementation.
This is a legacy function. The recommended alternative is String.ValidPos.get, combined with
String.pos! or another means of obtaining a String.ValidPos.
Examples
"abc".get! ⟨1⟩ = 'b'
Equations
- String.Pos.Raw.get! s p = String.Pos.Raw.utf8GetAux s.data 0 p
Instances For
Equations
- s.get! p = String.Pos.Raw.utf8GetAux s.data 0 p
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Equations
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The slice from the beginning of s up to p (exclusive).
Equations
- s.replaceEnd p = s.toSlice.replaceEnd p.toSlice
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The slice from p (inclusive) up to the end of s.
Equations
- s.replaceStart p = s.toSlice.replaceStart p.toSlice
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Replaces the character at a specified position in a string with a new character.
If both the replacement character and the replaced character are 7-bit ASCII characters and the string is not shared, then it is updated in-place and not copied.
Examples:
("abc".pos ⟨1⟩ (by decide)).set 'B' (by decide) = "aBc"("L∃∀N".pos ⟨4⟩ (by decide)).set 'X' (by decide) = "L∃XN"
Equations
- One or more equations did not get rendered due to their size.
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Given a valid position in a string, obtain the corresponding position after setting a character on that string, provided that the position was before the changed position.
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Replaces the character at position p in the string s with the result of applying f to that
character.
If both the replacement character and the replaced character are 7-bit ASCII characters and the string is not shared, then it is updated in-place and not copied.
Examples:
("abc".pos ⟨1⟩ (by decide)).modify Char.toUpper (by decide) = "aBc"
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Given a valid position in a string, obtain the corresponding position after modifying a character in that string, provided that the position was before the changed position.
Equations
- q.modifyOfLE p f hp hpq = { offset := q.offset, isValid := ⋯ }
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Replaces the character at a specified position in a string with a new character. If the position is invalid, the string is returned unchanged.
If both the replacement character and the replaced character are 7-bit ASCII characters and the string is not shared, then it is updated in-place and not copied.
This is a legacy function. The recommended alternative is String.ValidPos.set, combined with
String.pos or another means of obtaining a String.ValidPos.
Examples:
"abc".set ⟨1⟩ 'B' = "aBc""abc".set ⟨3⟩ 'D' = "abc""L∃∀N".set ⟨4⟩ 'X' = "L∃XN""L∃∀N".set ⟨2⟩ 'X' = "L∃∀N"because'∃'is a multi-byte character, so the byte index2is an invalid position.
Equations
- String.Pos.Raw.set x✝² x✝¹ x✝ = (String.Pos.Raw.utf8SetAux x✝ x✝².data 0 x✝¹).asString
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Replaces the character at position p in the string s with the result of applying f to that
character. If p is an invalid position, the string is returned unchanged.
If both the replacement character and the replaced character are 7-bit ASCII characters and the string is not shared, then it is updated in-place and not copied.
This is a legacy function. The recommended alternative is String.ValidPos.set, combined with
String.pos or another means of obtaining a String.ValidPos.
Examples:
"abc".modify ⟨1⟩ Char.toUpper = "aBc""abc".modify ⟨3⟩ Char.toUpper = "abc"
Equations
- String.Pos.Raw.modify s i f = String.Pos.Raw.set s i (f (String.Pos.Raw.get s i))
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Replaces the character at position p in the string s with the result of applying f to that
character. If p is an invalid position, the string is returned unchanged.
If both the replacement character and the replaced character are 7-bit ASCII characters and the string is not shared, then it is updated in-place and not copied.
This is a legacy function. The recommended alternative is String.ValidPos.set, combined with
String.pos or another means of obtaining a String.ValidPos.
Examples:
"abc".modify ⟨1⟩ Char.toUpper = "aBc""abc".modify ⟨3⟩ Char.toUpper = "abc"
Equations
- s.modify i f = String.Pos.Raw.set s i (f (String.Pos.Raw.get s i))
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Returns the next position in a string after position p. If p is not a valid position or
p = s.endPos, returns the position one byte after p.
A run-time bounds check is performed to determine whether p is at the end of the string. If a
bounds check has already been performed, use String.next' to avoid a repeated check.
This is a legacy function. The recommended alternative is String.ValidPos.next or one of its
variants like String.ValidPos.next?, combined with String.pos or another means of obtaining
a String.ValisPos.
Some examples of edge cases:
"abc".next ⟨3⟩ = ⟨4⟩, since3 = "abc".endPos"L∃∀N".next ⟨2⟩ = ⟨3⟩, since2points into the middle of a multi-byte UTF-8 character
Examples:
Equations
- String.Pos.Raw.next s p = p + String.Pos.Raw.get s p
Instances For
Equations
- s.next p = p + String.Pos.Raw.get s p
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Returns the position in a string before a specified position, p. If p = ⟨0⟩, returns 0. If p
is greater than endPos, returns the position one byte before p. Otherwise, if p occurs in the
middle of a multi-byte character, returns the beginning position of that character.
For example, "L∃∀N".prev ⟨3⟩ is ⟨1⟩, since byte 3 occurs in the middle of the multi-byte
character '∃' that starts at byte 1.
This is a legacy function. The recommended alternative is String.ValidPos.prev or one of its
variants like String.ValidPos.prev?, combined with String.pos or another means of obtaining
a String.ValidPos.
Examples:
"abc".get ("abc".endPos |> "abc".prev) = 'c'"L∃∀N".get ("L∃∀N".endPos |> "L∃∀N".prev |> "L∃∀N".prev |> "L∃∀N".prev) = '∃'
Equations
- String.Pos.Raw.prev x✝¹ x✝ = String.Pos.Raw.utf8PrevAux x✝¹.data 0 x✝
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Equations
- x✝¹.prev x✝ = String.Pos.Raw.utf8PrevAux x✝¹.data 0 x✝
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Equations
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Returns the last character in s. If s = "", returns (default : Char).
Examples:
Equations
- s.back = String.Pos.Raw.get s (String.Pos.Raw.prev s s.endPos)
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Returns true if a specified byte position is greater than or equal to the position which points to
the end of a string. Otherwise, returns false.
Examples:
(0 |> "abc".next |> "abc".next |> "abc".atEnd) = false(0 |> "abc".next |> "abc".next |> "abc".next |> "abc".next |> "abc".atEnd) = true(0 |> "L∃∀N".next |> "L∃∀N".next |> "L∃∀N".next |> "L∃∀N".atEnd) = false(0 |> "L∃∀N".next |> "L∃∀N".next |> "L∃∀N".next |> "L∃∀N".next |> "L∃∀N".atEnd) = true"abc".atEnd ⟨4⟩ = true"L∃∀N".atEnd ⟨7⟩ = false"L∃∀N".atEnd ⟨8⟩ = true
Equations
- String.Pos.Raw.atEnd x✝¹ x✝ = decide (x✝.byteIdx ≥ x✝¹.utf8ByteSize)
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Returns the character at position p of a string. Returns (default : Char), which is 'A', if
p is not a valid position.
Requires evidence, h, that p is within bounds instead of performing a run-time bounds check as
in String.get.
A typical pattern combines get' with a dependent if-expression to avoid the overhead of an
additional bounds check. For example:
def getInBounds? (s : String) (p : String.Pos) : Option Char :=
if h : s.atEnd p then none else some (s.get' p h)
Even with evidence of ¬ s.atEnd p, p may be invalid if a byte index points into the middle of a
multi-byte UTF-8 character. For example, "L∃∀N".get' ⟨2⟩ (by decide) = (default : Char).
This is a legacy function. The recommended alternative is String.ValidPos.get, combined with
String.pos or another means of obtaining a String.ValidPos.
Examples:
"abc".get' 0 (by decide) = 'a'let lean := "L∃∀N"; lean.get' (0 |> lean.next |> lean.next) (by decide) = '∀'
Equations
- String.Pos.Raw.get' s p h = String.Pos.Raw.utf8GetAux s.data 0 p
Instances For
Equations
- s.get' p h = String.Pos.Raw.utf8GetAux s.data 0 p
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Returns the next position in a string after position p. The result is unspecified if p is not a
valid position.
Requires evidence, h, that p is within bounds. No run-time bounds check is performed, as in
String.next.
A typical pattern combines String.next' with a dependent if-expression to avoid the overhead of
an additional bounds check. For example:
def next? (s : String) (p : String.Pos) : Option Char :=
if h : s.atEnd p then none else s.get (s.next' p h)
This is a legacy function. The recommended alternative is String.ValidPos.next, combined with
String.pos or another means of obtaining a String.ValidPos.
Example:
Equations
- String.Pos.Raw.next' s p h = p + String.Pos.Raw.get s p
Instances For
Equations
- s.next' p h = p + String.Pos.Raw.get s p
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Finds the position of the first character in a string for which the Boolean predicate p returns
true. If there is no such character in the string, then the end position of the string is
returned.
Examples:
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Equations
- s.revFindAux p pos = if h : pos = 0 then none else have this := ⋯; have pos := String.Pos.Raw.prev s pos; if p (String.Pos.Raw.get s pos) = true then some pos else s.revFindAux p pos
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Finds the position of the last character in a string for which the Boolean predicate p returns
true. If there is no such character in the string, then none is returned.
Examples:
"coffee tea water".revFind (·.isWhitespace) = some ⟨10⟩"tea".revFind (· == 'X') = none"".revFind (· == 'X') = none
Equations
- s.revFind p = s.revFindAux p s.endPos
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- String.Pos.Raw.Internal.minImpl p₁ p₂ = p₁.min p₂
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Returns the first position where the two strings differ.
If one string is a prefix of the other, then the returned position is the end position of the shorter string. If the strings are identical, then their end position is returned.
Examples:
"tea".firstDiffPos "ten" = ⟨2⟩"tea".firstDiffPos "tea" = ⟨3⟩"tea".firstDiffPos "teas" = ⟨3⟩"teas".firstDiffPos "tea" = ⟨3⟩
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- a.firstDiffPos b = String.firstDiffPos.loop a b (a.endPos.min b.endPos) 0
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Creates a new string that consists of the region of the input string delimited by the two positions.
The result is "" if the start position is greater than or equal to the end position or if the
start position is at the end of the string. If either position is invalid (that is, if either points
at the middle of a multi-byte UTF-8 character) then the result is unspecified.
This is a legacy function. The recommended alternative is String.ValidPos.extract, but usually
it is even better to operate on String.Slice instead and call String.Slice.copy (only) if
required.
Examples:
"red green blue".extract ⟨0⟩ ⟨3⟩ = "red""red green blue".extract ⟨3⟩ ⟨0⟩ = """red green blue".extract ⟨0⟩ ⟨100⟩ = "red green blue""red green blue".extract ⟨4⟩ ⟨100⟩ = "green blue""L∃∀N".extract ⟨1⟩ ⟨2⟩ = "∃∀N""L∃∀N".extract ⟨2⟩ ⟨100⟩ = ""
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- String.Pos.Raw.extract.go₁ [] x✝² x✝¹ x✝ = []
- String.Pos.Raw.extract.go₁ (c :: cs) x✝² x✝¹ x✝ = if x✝² = x✝¹ then String.Pos.Raw.extract.go₂ (c :: cs) x✝² x✝ else String.Pos.Raw.extract.go₁ cs (x✝² + c) x✝¹ x✝
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Equations
- x✝².extract x✝¹ x✝ = String.Pos.Raw.extract x✝² x✝¹ x✝
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Splits a string at each character for which p returns true.
The characters that satisfy p are not included in any of the resulting strings. If multiple
characters in a row satisfy p, then the resulting list will contain empty strings.
Examples:
"coffee tea water".split (·.isWhitespace) = ["coffee", "tea", "water"]"coffee tea water".split (·.isWhitespace) = ["coffee", "", "tea", "", "water"]"fun x =>\n x + 1\n".split (· == '\n') = ["fun x =>", " x + 1", ""]
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- s.splitToList p = s.splitAux p 0 0 []
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- s.split p = s.splitToList p
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Auxiliary for splitOn. Preconditions:
It represents the state where we have currently parsed some split parts into r (in reverse order),
b is the beginning of the string / the end of the previous match of sep, and the first j bytes
of sep match the bytes i-j .. i of s.
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Splits a string s on occurrences of the separator string sep. The default separator is " ".
When sep is empty, the result is [s]. When sep occurs in overlapping patterns, the first match
is taken. There will always be exactly n+1 elements in the returned list if there were n
non-overlapping matches of sep in the string. The separators are not included in the returned
substrings.
Examples:
"here is some text ".splitOn = ["here", "is", "some", "text", ""]"here is some text ".splitOn "some" = ["here is ", " text "]"here is some text ".splitOn "" = ["here is some text "]"ababacabac".splitOn "aba" = ["", "bac", "c"]
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Equations
- String.instInhabited_1 = { default := "" }
Equations
- String.instAppend = { append := String.append }
Adds multiple repetitions of a character to the end of a string.
Returns s, with n repetitions of c at the end. Internally, the implementation repeatedly calls
String.push, so the string is modified in-place if there is a unique reference to it.
Examples:
Equations
- s.pushn c n = Nat.repeat (fun (s : String) => s.push c) n s
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Appends all the strings in a list of strings, in order.
Use String.intercalate to place a separator string between the strings in a list.
Examples:
String.join ["gr", "ee", "n"] = "green"String.join ["b", "", "l", "", "ue"] = "blue"String.join [] = ""
Equations
- String.join l = List.foldl (fun (r s : String) => r ++ s) "" l
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Appends the strings in a list of strings, placing the separator s between each pair.
Examples:
", ".intercalate ["red", "green", "blue"] = "red, green, blue"" and ".intercalate ["tea", "coffee"] = "tea and coffee"" | ".intercalate ["M", "", "N"] = "M | | N"
Equations
- s.intercalate [] = ""
- s.intercalate (a :: as) = String.intercalate.go✝ a s as
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An iterator over the characters (Unicode code points) in a String. Typically created by
String.iter.
String iterators pair a string with a valid byte index. This allows efficient character-by-character processing of strings while avoiding the need to manually ensure that byte indices are used with the correct strings.
An iterator is valid if the position i is valid for the string s, meaning 0 ≤ i ≤ s.endPos
and i lies on a UTF8 byte boundary. If i = s.endPos, the iterator is at the end of the string.
Most operations on iterators return unspecified values if the iterator is not valid. The functions
in the String.Iterator API rule out the creation of invalid iterators, with two exceptions:
Iterator.next iteris invalid ifiteris already at the end of the string (iter.atEndistrue), andIterator.forward iter n/Iterator.nextn iter nis invalid ifnis strictly greater than the number of remaining characters.
- s : String
The string being iterated over.
- i : Pos.Raw
The current UTF-8 byte position in the string
s.This position is not guaranteed to be valid for the string. If the position is not valid, then the current character is
(default : Char), similar toString.geton an invalid position.
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Creates an iterator at the beginning of the string.
Equations
- s.mkIterator = { s := s, i := 0 }
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Creates an iterator at the beginning of the string.
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The size of a string iterator is the number of bytes remaining.
Recursive functions that iterate towards the end of a string will typically decrease this measure.
Equations
- String.instSizeOfIterator = { sizeOf := fun (i : String.Iterator) => i.s.utf8ByteSize - i.i.byteIdx }
The string being iterated over.
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The current UTF-8 byte position in the string s.
This position is not guaranteed to be valid for the string. If the position is not valid, then the
current character is (default : Char), similar to String.get on an invalid position.
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Gets the character at the iterator's current position.
A run-time bounds check is performed. Use String.Iterator.curr' to avoid redundant bounds checks.
If the position is invalid, returns (default : Char).
Equations
- { s := s, i := i }.curr = String.Pos.Raw.get s i
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Moves the iterator's position forward by one character, unconditionally.
It is only valid to call this function if the iterator is not at the end of the string (i.e.
if Iterator.atEnd is false); otherwise, the resulting iterator will be invalid.
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Moves the iterator's position backward by one character, unconditionally.
The position is not changed if the iterator is at the beginning of the string.
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Gets the character at the iterator's current position.
The proof of it.hasNext ensures that there is, in fact, a character at the current position. This
function is faster that String.Iterator.curr due to avoiding a run-time bounds check.
Equations
- { s := s, i := i }.curr' h_2 = String.Pos.Raw.get' s i ⋯
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Moves the iterator's position forward by one character, unconditionally.
The proof of it.hasNext ensures that there is, in fact, a position that's one character forwards.
This function is faster that String.Iterator.next due to avoiding a run-time bounds check.
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Replaces the current character in the string.
Does nothing if the iterator is at the end of the string. If both the replacement character and the replaced character are 7-bit ASCII characters and the string is not shared, then it is updated in-place and not copied.
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Extracts the substring between the positions of two iterators. The first iterator's position is the start of the substring, and the second iterator's position is the end.
Returns the empty string if the iterators are for different strings, or if the position of the first iterator is past the position of the second iterator.
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Moves the iterator's position forward by the specified number of characters.
The resulting iterator is only valid if the number of characters to skip is less than or equal to the number of characters left in the iterator.
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The remaining characters in an iterator, as a string.
Equations
- { s := s, i := i }.remainingToString = String.Pos.Raw.extract s i s.endPos
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Moves the iterator's position forward by the specified number of characters.
The resulting iterator is only valid if the number of characters to skip is less than or equal to the number of characters left in the iterator.
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Returns the character index that corresponds to the provided position (i.e. UTF-8 byte index) in a string.
If the position is at the end of the string, then the string's length in characters is returned. If the position is invalid due to pointing at the middle of a UTF-8 byte sequence, then the character index of the next character after the position is returned.
Examples:
"L∃∀N".offsetOfPos ⟨0⟩ = 0"L∃∀N".offsetOfPos ⟨1⟩ = 1"L∃∀N".offsetOfPos ⟨2⟩ = 2"L∃∀N".offsetOfPos ⟨4⟩ = 2"L∃∀N".offsetOfPos ⟨5⟩ = 3"L∃∀N".offsetOfPos ⟨50⟩ = 4
Equations
- s.offsetOfPos pos = s.offsetOfPosAux pos 0 0
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- String.Internal.offsetOfPosImpl s pos = s.offsetOfPos pos
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- String.foldlAux f s stopPos i a = if h : i < stopPos then have this := ⋯; String.foldlAux f s stopPos (String.Pos.Raw.next s i) (f a (String.Pos.Raw.get s i)) else a
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Folds a function over a string from the left, accumulating a value starting with init. The
accumulated value is combined with each character in order, using f.
Examples:
"coffee tea water".foldl (fun n c => if c.isWhitespace then n + 1 else n) 0 = 2"coffee tea and water".foldl (fun n c => if c.isWhitespace then n + 1 else n) 0 = 3"coffee tea water".foldl (·.push ·) "" = "coffee tea water"
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- String.foldl f init s = String.foldlAux f s s.endPos 0 init
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- String.Internal.foldlImpl f init s = String.foldl f init s
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Folds a function over a string from the right, accumulating a value starting with init. The
accumulated value is combined with each character in reverse order, using f.
Examples:
"coffee tea water".foldr (fun c n => if c.isWhitespace then n + 1 else n) 0 = 2"coffee tea and water".foldr (fun c n => if c.isWhitespace then n + 1 else n) 0 = 3"coffee tea water".foldr (fun c s => c.push s) "" = "retaw dna aet eeffoc"
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- String.foldr f init s = String.foldrAux f init s s.endPos 0
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Checks whether there is a character in a string for which the Boolean predicate p returns true.
Short-circuits at the first character for which p returns true.
Examples:
"brown".any (·.isLetter) = true"brown".any (·.isWhitespace) = false"brown and orange".any (·.isLetter) = true"".any (fun _ => false) = false
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- String.Internal.containsImpl s c = s.contains c
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Applies the function f to every character in a string, returning a string that contains the
resulting characters.
Examples:
"abc123".map Char.toUpper = "ABC123""".map Char.toUpper = ""
Equations
- String.map f s = String.mapAux f 0 s
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Checks whether the string can be interpreted as the decimal representation of a natural number.
A string can be interpreted as a decimal natural number if it is not empty and all the characters in it are digits.
Use String.toNat? or String.toNat! to convert such a string to a natural number.
Examples:
"".isNat = false"0".isNat = true"5".isNat = true"05".isNat = true"587".isNat = true"-587".isNat = false" 5".isNat = false"2+3".isNat = false"0xff".isNat = false
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Interprets a string as the decimal representation of a natural number, returning it. Returns none
if the string does not contain a decimal natural number.
A string can be interpreted as a decimal natural number if it is not empty and all the characters in it are digits.
Use String.isNat to check whether String.toNat? would return some. String.toNat! is an
alternative that panics instead of returning none when the string is not a natural number.
Examples:
"".toNat? = none"0".toNat? = some 0"5".toNat? = some 5"587".toNat? = some 587"-587".toNat? = none" 5".toNat? = none"2+3".toNat? = none"0xff".toNat? = none
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Checks whether substrings of two strings are equal. Substrings are indicated by their starting
positions and a size in UTF-8 bytes. Returns false if the indicated substring does not exist in
either string.
This is a legacy function. The recommended alternative is to construct slices representing the
strings to be compared and use the BEq instance of String.Slice.
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Checks whether the first string (p) is a prefix of the second (s).
String.startsWith is a version that takes the potential prefix after the string.
Examples:
"red".isPrefixOf "red green blue" = true"green".isPrefixOf "red green blue" = false"".isPrefixOf "red green blue" = true
Equations
- p.isPrefixOf s = String.Pos.Raw.substrEq p 0 s 0 p.endPos.byteIdx
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Returns the position of the beginning of the line that contains the position pos.
Lines are ended by '\n', and the returned position is either 0 : String.Pos or immediately after
a '\n' character.
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Copies the region of the underlying string pointed to by a substring into a fresh string.
Equations
- { str := s, startPos := b, stopPos := e }.toString = String.Pos.Raw.extract s b e
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Returns an iterator into the underlying string, at the substring's starting position. The ending position is discarded, so the iterator alone cannot be used to determine whether its current position is within the original substring.
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Returns the character at the given position in the substring.
The position is relative to the substring, rather than the underlying string, and no bounds checking
is performed with respect to the substring's end position. If the relative position is not a valid
position in the underlying string, the fallback value (default : Char), which is 'A', is
returned. Does not panic.
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Returns the next position in a substring after the given position. If the position is at the end of the substring, it is returned unmodified.
Both the input position and the returned position are interpreted relative to the substring's start position, not the underlying string.
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Returns the previous position in a substring, just prior to the given position. If the position is at the beginning of the substring, it is returned unmodified.
Both the input position and the returned position are interpreted relative to the substring's start position, not the underlying string.
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Returns the position that's the specified number of characters forward from the given position in a substring. If the end position of the substring is reached, it is returned.
Both the input position and the returned position are interpreted relative to the substring's start position, not the underlying string.
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Returns the position that's the specified number of characters prior to the given position in a substring. If the start position of the substring is reached, it is returned.
Both the input position and the returned position are interpreted relative to the substring's start position, not the underlying string.
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Returns the first character in the substring.
If the substring is empty, but the substring's start position is a valid position in the underlying
string, then the character at the start position is returned. If the substring's start position is
not a valid position in the string, the fallback value (default : Char), which is 'A', is
returned. Does not panic.
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Returns the substring-relative position of the first occurrence of c in s, or s.bsize if c
doesn't occur.
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Removes the specified number of characters (Unicode code points) from the beginning of a substring by advancing its start position.
If the substring's end position is reached, the start position is not advanced past it.
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Removes the specified number of characters (Unicode code points) from the end of a substring by moving its end position towards its start position.
If the substring's start position is reached, the end position is not retracted past it.
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Retains only the specified number of characters (Unicode code points) at the beginning of a substring, by moving its end position towards its start position.
If the substring's start position is reached, the end position is not retracted past it.
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Retains only the specified number of characters (Unicode code points) at the end of a substring, by moving its start position towards its end position.
If the substring's end position is reached, the start position is not advanced past it.
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Checks whether a position in a substring is precisely equal to its ending position.
The position is understood relative to the substring's starting position, rather than the underlying string's starting position.
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Returns the region of the substring delimited by the provided start and stop positions, as a substring. The positions are interpreted with respect to the substring's start position, rather than the underlying string.
If the resulting substring is empty, then the resulting substring is a substring of the empty string
"". Otherwise, the underlying string is that of the input substring with the beginning and end
positions adjusted.
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Splits a substring s on occurrences of the separator string sep. The default separator is " ".
When sep is empty, the result is [s]. When sep occurs in overlapping patterns, the first match
is taken. There will always be exactly n+1 elements in the returned list if there were n
non-overlapping matches of sep in the string. The separators are not included in the returned
substrings, which are all substrings of s's string.
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Folds a function over a substring from the left, accumulating a value starting with init. The
accumulated value is combined with each character in order, using f.
Equations
- Substring.foldl f init { str := s_1, startPos := b, stopPos := e } = String.foldlAux f s_1 e b init
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Folds a function over a substring from the right, accumulating a value starting with init. The
accumulated value is combined with each character in reverse order, using f.
Equations
- Substring.foldr f init { str := s_1, startPos := b, stopPos := e } = String.foldrAux f init s_1 e b
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Checks whether the Boolean predicate p returns true for any character in a substring.
Short-circuits at the first character for which p returns true.
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Retains only the longest prefix of a substring in which a Boolean predicate returns true for all
characters by moving the substring's end position towards its start position.
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Removes the longest prefix of a substring in which a Boolean predicate returns true for all
characters by moving the substring's start position. The start position is moved to the position of
the first character for which the predicate returns false, or to the substring's end position if
the predicate always returns true.
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Retains only the longest suffix of a substring in which a Boolean predicate returns true for all
characters by moving the substring's start position towards its end position.
Equations
- { str := s, startPos := b, stopPos := e }.takeRightWhile x✝ = { str := s, startPos := Substring.takeRightWhileAux s b x✝ e, stopPos := e }
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Removes the longest suffix of a substring in which a Boolean predicate returns true for all
characters by moving the substring's end position. The end position is moved just after the position
of the last character for which the predicate returns false, or to the substring's start position
if the predicate always returns true.
Equations
- { str := s, startPos := b, stopPos := e }.dropRightWhile x✝ = { str := s, startPos := b, stopPos := Substring.takeRightWhileAux s b x✝ e }
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Removes leading whitespace from a substring by moving its start position to the first non-whitespace character, or to its end position if there is no non-whitespace character.
“Whitespace” is defined as characters for which Char.isWhitespace returns true.
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Removes trailing whitespace from a substring by moving its end position to the last non-whitespace character, or to its start position if there is no non-whitespace character.
“Whitespace” is defined as characters for which Char.isWhitespace returns true.
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Removes leading and trailing whitespace from a substring by first moving its start position to the first non-whitespace character, and then moving its end position to the last non-whitespace character.
If the substring consists only of whitespace, then the resulting substring's start position is moved to its end position.
“Whitespace” is defined as characters for which Char.isWhitespace returns true.
Examples:
" red green blue ".toSubstring.trim.toString = "red green blue"" red green blue ".toSubstring.trim.startPos = ⟨1⟩" red green blue ".toSubstring.trim.stopPos = ⟨15⟩" ".toSubstring.trim.startPos = ⟨5⟩
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Checks whether the substring can be interpreted as the decimal representation of a natural number.
A substring can be interpreted as a decimal natural number if it is not empty and all the characters in it are digits.
Use Substring.toNat? to convert such a substring to a natural number.
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Checks whether the substring can be interpreted as the decimal representation of a natural number, returning the number if it can.
A substring can be interpreted as a decimal natural number if it is not empty and all the characters in it are digits.
Use Substring.isNat to check whether the substring is such a substring.
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Given a Substring, returns another one which has valid endpoints
and represents the same substring according to Substring.toString.
(Note, the substring may still be inverted, i.e. beginning greater than end.)
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Checks whether two substrings represent equal strings. Usually accessed via the == operator.
Two substrings do not need to have the same underlying string or the same start and end positions; instead, they are equal if they contain the same sequence of characters.
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Returns the longest common prefix of two substrings.
The returned substring uses the same underlying string as s.
Equations
- s.commonPrefix t = { str := s.str, startPos := s.startPos, stopPos := Substring.commonPrefix.loop✝ s t s.startPos t.startPos }
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Returns the longest common suffix of two substrings.
The returned substring uses the same underlying string as s.
Equations
- s.commonSuffix t = { str := s.str, startPos := Substring.commonSuffix.loop✝ s t s.stopPos t.stopPos, stopPos := s.stopPos }
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Removes the specified number of characters (Unicode code points) from the start of the string.
If n is greater than s.length, returns "".
Examples:
"red green blue".drop 4 = "green blue""red green blue".drop 10 = "blue""red green blue".drop 50 = ""
Equations
- s.drop n = (s.toSubstring.drop n).toString
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Removes the specified number of characters (Unicode code points) from the end of the string.
If n is greater than s.length, returns "".
Examples:
"red green blue".dropRight 5 = "red green""red green blue".dropRight 11 = "red""red green blue".dropRight 50 = ""
Equations
- s.dropRight n = (s.toSubstring.dropRight n).toString
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- String.Internal.dropRightImpl s n = s.dropRight n
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Creates a new string that contains the first n characters (Unicode code points) of s.
If n is greater than s.length, returns s.
Examples:
"red green blue".take 3 = "red""red green blue".take 1 = "r""red green blue".take 0 = """red green blue".take 100 = "red green blue"
Equations
- s.take n = (s.toSubstring.take n).toString
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Creates a new string that contains the last n characters (Unicode code points) of s.
If n is greater than s.length, returns s.
Examples:
"red green blue".takeRight 4 = "blue""red green blue".takeRight 1 = "e""red green blue".takeRight 0 = """red green blue".takeRight 100 = "red green blue"
Equations
- s.takeRight n = (s.toSubstring.takeRight n).toString
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Creates a new string that contains the longest prefix of s in which p returns true for all
characters.
Examples:
"red green blue".takeWhile (·.isLetter) = "red""red green blue".takeWhile (· == 'r') = "r""red green blue".takeWhile (· != 'n') = "red gree""red green blue".takeWhile (fun _ => true) = "red green blue"
Equations
- s.takeWhile p = (s.toSubstring.takeWhile p).toString
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Creates a new string by removing the longest prefix from s in which p returns true for all
characters.
Examples:
"red green blue".dropWhile (·.isLetter) = " green blue""red green blue".dropWhile (· == 'r') = "ed green blue""red green blue".dropWhile (· != 'n') = "n blue""red green blue".dropWhile (fun _ => true) = ""
Equations
- s.dropWhile p = (s.toSubstring.dropWhile p).toString
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Creates a new string that contains the longest suffix of s in which p returns true for all
characters.
Examples:
"red green blue".takeRightWhile (·.isLetter) = "blue""red green blue".takeRightWhile (· == 'e') = "e""red green blue".takeRightWhile (· != 'n') = " blue""red green blue".takeRightWhile (fun _ => true) = "red green blue"
Equations
- s.takeRightWhile p = (s.toSubstring.takeRightWhile p).toString
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Creates a new string by removing the longest suffix from s in which p returns true for all
characters.
Examples:
"red green blue".dropRightWhile (·.isLetter) = "red green ""red green blue".dropRightWhile (· == 'e') = "red green blu""red green blue".dropRightWhile (· != 'n') = "red green""red green blue".dropRightWhile (fun _ => true) = ""
Equations
- s.dropRightWhile p = (s.toSubstring.dropRightWhile p).toString
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Checks whether the first string (s) begins with the second (pre).
String.isPrefix is a version that takes the potential prefix before the string.
Examples:
"red green blue".startsWith "red" = true"red green blue".startsWith "green" = false"red green blue".startsWith "" = true"red".startsWith "red" = true
Equations
- s.startsWith pre = (s.toSubstring.take pre.length == pre.toSubstring)
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Checks whether the first string (s) ends with the second (post).
Examples:
"red green blue".endsWith "blue" = true"red green blue".endsWith "green" = false"red green blue".endsWith "" = true"red".endsWith "red" = true
Equations
- s.endsWith post = (s.toSubstring.takeRight post.length == post.toSubstring)
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Removes trailing whitespace from a string.
“Whitespace” is defined as characters for which Char.isWhitespace returns true.
Examples:
"abc".trimRight = "abc"" abc".trimRight = " abc""abc \t ".trimRight = "abc"" abc ".trimRight = " abc""abc\ndef\n".trimRight = "abc\ndef"
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Removes leading whitespace from a string.
“Whitespace” is defined as characters for which Char.isWhitespace returns true.
Examples:
"abc".trimLeft = "abc"" abc".trimLeft = " abc""abc \t ".trimLeft = "abc \t "" abc ".trimLeft = "abc ""abc\ndef\n".trimLeft = "abc\ndef\n"
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Removes leading and trailing whitespace from a string.
“Whitespace” is defined as characters for which Char.isWhitespace returns true.
Examples:
"abc".trim = "abc"" abc".trim = "abc""abc \t ".trim = "abc"" abc ".trim = "abc""abc\ndef\n".trim = "abc\ndef"
Equations
- s.trim = s.toSubstring.trim.toString
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Repeatedly increments a position in a string, as if by String.next, while the predicate p
returns true for the character at the position. Stops incrementing at the end of the string or
when p returns false for the current character.
Examples:
let s := " a "; s.get (s.nextWhile Char.isWhitespace 0) = 'a'let s := "a "; s.get (s.nextWhile Char.isWhitespace 0) = 'a'let s := "ba "; s.get (s.nextWhile Char.isWhitespace 0) = 'b'
Equations
- String.Pos.Raw.nextWhile s p i = Substring.takeWhileAux s s.endPos p i
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Equations
- s.nextWhile p i = String.Pos.Raw.nextWhile s p i
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Equations
- String.Internal.nextWhileImpl s p i = String.Pos.Raw.nextWhile s p i
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Repeatedly increments a position in a string, as if by String.next, while the predicate p
returns false for the character at the position. Stops incrementing at the end of the string or
when p returns true for the current character.
Examples:
let s := " a "; s.get (s.nextUntil Char.isWhitespace 0) = ' 'let s := " a "; s.get (s.nextUntil Char.isLetter 0) = 'a'let s := "a "; s.get (s.nextUntil Char.isWhitespace 0) = ' '
Equations
- String.Pos.Raw.nextUntil s p i = String.Pos.Raw.nextWhile s (fun (c : Char) => !p c) i
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Equations
- s.nextUntil p i = String.Pos.Raw.nextUntil s p i
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Replaces each character in s with the result of applying Char.toUpper to it.
Char.toUpper has no effect on characters outside of the range 'a'–'z'.
Examples:
Equations
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Replaces each character in s with the result of applying Char.toLower to it.
Char.toLower has no effect on characters outside of the range 'A'–'Z'.
Examples:
Equations
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Replaces the first character in s with the result of applying Char.toUpper to it. Returns the
empty string if the string is empty.
Char.toUpper has no effect on characters outside of the range 'a'–'z'.
Examples:
"orange".capitalize = "Orange""ORANGE".capitalize = "ORANGE""".capitalize = ""
Equations
- s.capitalize = String.Pos.Raw.set s 0 (String.Pos.Raw.get s 0).toUpper
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Replaces the first character in s with the result of applying Char.toLower to it. Returns the
empty string if the string is empty.
Char.toLower has no effect on characters outside of the range 'A'–'Z'.
Examples:
"Orange".decapitalize = "orange""ORANGE".decapitalize = "oRANGE""".decapitalize = ""
Equations
- s.decapitalize = String.Pos.Raw.set s 0 (String.Pos.Raw.get s 0).toLower
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If pre is a prefix of s, returns the remainder. Returns none otherwise.
The string pre is a prefix of s if there exists a t : String such that s = pre ++ t. If so,
the result is some t.
Use String.stripPrefix to return the string unchanged when pre is not a prefix.
Examples:
"red green blue".dropPrefix? "red " = some "green blue""red green blue".dropPrefix? "reed " = none"red green blue".dropPrefix? "" = some "red green blue"
Equations
- s.dropPrefix? pre = s.toSubstring.dropPrefix? pre.toSubstring
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If suff is a suffix of s, returns the remainder. Returns none otherwise.
The string suff is a suffix of s if there exists a t : String such that s = t ++ suff. If so,
the result is some t.
Use String.stripSuffix to return the string unchanged when suff is not a suffix.
Examples:
"red green blue".dropSuffix? " blue" = some "red green""red green blue".dropSuffix? " blu " = none"red green blue".dropSuffix? "" = some "red green blue"
Equations
- s.dropSuffix? suff = s.toSubstring.dropSuffix? suff.toSubstring
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If pre is a prefix of s, returns the remainder. Returns s unmodified otherwise.
The string pre is a prefix of s if there exists a t : String such that s = pre ++ t. If so,
the result is t. Otherwise, it is s.
Use String.dropPrefix? to return none when pre is not a prefix.
Examples:
"red green blue".stripPrefix "red " = "green blue""red green blue".stripPrefix "reed " = "red green blue""red green blue".stripPrefix "" = "red green blue"
Equations
- s.stripPrefix pre = (Option.map Substring.toString (s.dropPrefix? pre)).getD s
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If suff is a suffix of s, returns the remainder. Returns s unmodified otherwise.
The string suff is a suffix of s if there exists a t : String such that s = t ++ suff. If so,
the result is t. Otherwise, it is s.
Use String.dropSuffix? to return none when suff is not a suffix.
Examples:
"red green blue".stripSuffix " blue" = "red green""red green blue".stripSuffix " blu " = "red green blue""red green blue".stripSuffix "" = "red green blue"
Equations
- s.stripSuffix suff = (Option.map Substring.toString (s.dropSuffix? suff)).getD s